3c=c+12,

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Solution for 3c=c+12, equation:



3c=c+12.
We move all terms to the left:
3c-(c+12.)=0
We add all the numbers together, and all the variables
3c-(c+12)=0
We get rid of parentheses
3c-c-12=0
We add all the numbers together, and all the variables
2c-12=0
We move all terms containing c to the left, all other terms to the right
2c=12
c=12/2
c=6

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