3cos(2x)+4cos(x)+1=0

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Solution for 3cos(2x)+4cos(x)+1=0 equation:


Simplifying
3cos(2x) + 4cos(x) + 1 = 0

Remove parenthesis around (2x)
3cos * 2x + 4cos(x) + 1 = 0

Reorder the terms for easier multiplication:
3 * 2cos * x + 4cos(x) + 1 = 0

Multiply 3 * 2
6cos * x + 4cos(x) + 1 = 0

Multiply cos * x
6cosx + 4cos(x) + 1 = 0

Multiply cos * x
6cosx + 4cosx + 1 = 0

Reorder the terms:
1 + 6cosx + 4cosx = 0

Combine like terms: 6cosx + 4cosx = 10cosx
1 + 10cosx = 0

Solving
1 + 10cosx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 10cosx = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 10cosx = 0 + -1
10cosx = 0 + -1

Combine like terms: 0 + -1 = -1
10cosx = -1

Divide each side by '10osx'.
c = -0.1o-1s-1x-1

Simplifying
c = -0.1o-1s-1x-1

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