3cos(2x)+5sin(x)-4=0

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Solution for 3cos(2x)+5sin(x)-4=0 equation:


Simplifying
3cos(2x) + 5sin(x) + -4 = 0

Remove parenthesis around (2x)
3cos * 2x + 5sin(x) + -4 = 0

Reorder the terms for easier multiplication:
3 * 2cos * x + 5sin(x) + -4 = 0

Multiply 3 * 2
6cos * x + 5sin(x) + -4 = 0

Multiply cos * x
6cosx + 5sin(x) + -4 = 0

Multiply ins * x
6cosx + 5insx + -4 = 0

Reorder the terms:
-4 + 6cosx + 5insx = 0

Solving
-4 + 6cosx + 5insx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 6cosx + 4 + 5insx = 0 + 4

Reorder the terms:
-4 + 4 + 6cosx + 5insx = 0 + 4

Combine like terms: -4 + 4 = 0
0 + 6cosx + 5insx = 0 + 4
6cosx + 5insx = 0 + 4

Combine like terms: 0 + 4 = 4
6cosx + 5insx = 4

Add '-5insx' to each side of the equation.
6cosx + 5insx + -5insx = 4 + -5insx

Combine like terms: 5insx + -5insx = 0
6cosx + 0 = 4 + -5insx
6cosx = 4 + -5insx

Divide each side by '6osx'.
c = 0.6666666667o-1s-1x-1 + -0.8333333333ino-1

Simplifying
c = 0.6666666667o-1s-1x-1 + -0.8333333333ino-1

Reorder the terms:
c = -0.8333333333ino-1 + 0.6666666667o-1s-1x-1

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