3cos(2x)+cos(x)+2=0

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Solution for 3cos(2x)+cos(x)+2=0 equation:


Simplifying
3cos(2x) + cos(x) + 2 = 0

Remove parenthesis around (2x)
3cos * 2x + cos(x) + 2 = 0

Reorder the terms for easier multiplication:
3 * 2cos * x + cos(x) + 2 = 0

Multiply 3 * 2
6cos * x + cos(x) + 2 = 0

Multiply cos * x
6cosx + cos(x) + 2 = 0

Multiply cos * x
6cosx + cosx + 2 = 0

Reorder the terms:
2 + 6cosx + cosx = 0

Combine like terms: 6cosx + cosx = 7cosx
2 + 7cosx = 0

Solving
2 + 7cosx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 7cosx = 0 + -2

Combine like terms: 2 + -2 = 0
0 + 7cosx = 0 + -2
7cosx = 0 + -2

Combine like terms: 0 + -2 = -2
7cosx = -2

Divide each side by '7osx'.
c = -0.2857142857o-1s-1x-1

Simplifying
c = -0.2857142857o-1s-1x-1

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