3cos(2x)+sin(x)+2=0

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Solution for 3cos(2x)+sin(x)+2=0 equation:


Simplifying
3cos(2x) + sin(x) + 2 = 0

Remove parenthesis around (2x)
3cos * 2x + sin(x) + 2 = 0

Reorder the terms for easier multiplication:
3 * 2cos * x + sin(x) + 2 = 0

Multiply 3 * 2
6cos * x + sin(x) + 2 = 0

Multiply cos * x
6cosx + sin(x) + 2 = 0

Multiply ins * x
6cosx + insx + 2 = 0

Reorder the terms:
2 + 6cosx + insx = 0

Solving
2 + 6cosx + insx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + 6cosx + -2 + insx = 0 + -2

Reorder the terms:
2 + -2 + 6cosx + insx = 0 + -2

Combine like terms: 2 + -2 = 0
0 + 6cosx + insx = 0 + -2
6cosx + insx = 0 + -2

Combine like terms: 0 + -2 = -2
6cosx + insx = -2

Add '-1insx' to each side of the equation.
6cosx + insx + -1insx = -2 + -1insx

Combine like terms: insx + -1insx = 0
6cosx + 0 = -2 + -1insx
6cosx = -2 + -1insx

Divide each side by '6osx'.
c = -0.3333333333o-1s-1x-1 + -0.1666666667ino-1

Simplifying
c = -0.3333333333o-1s-1x-1 + -0.1666666667ino-1

Reorder the terms:
c = -0.1666666667ino-1 + -0.3333333333o-1s-1x-1

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