3cos(2x)-5cos(x)-1=0

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Solution for 3cos(2x)-5cos(x)-1=0 equation:


Simplifying
3cos(2x) + -5cos(x) + -1 = 0

Remove parenthesis around (2x)
3cos * 2x + -5cos(x) + -1 = 0

Reorder the terms for easier multiplication:
3 * 2cos * x + -5cos(x) + -1 = 0

Multiply 3 * 2
6cos * x + -5cos(x) + -1 = 0

Multiply cos * x
6cosx + -5cos(x) + -1 = 0

Multiply cos * x
6cosx + -5cosx + -1 = 0

Reorder the terms:
-1 + 6cosx + -5cosx = 0

Combine like terms: 6cosx + -5cosx = 1cosx
-1 + 1cosx = 0

Solving
-1 + 1cosx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 1cosx = 0 + 1

Combine like terms: -1 + 1 = 0
0 + 1cosx = 0 + 1
1cosx = 0 + 1

Combine like terms: 0 + 1 = 1
1cosx = 1

Divide each side by '1osx'.
c = o-1s-1x-1

Simplifying
c = o-1s-1x-1

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