3cos(2x)-7cos(x)+5=0

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Solution for 3cos(2x)-7cos(x)+5=0 equation:


Simplifying
3cos(2x) + -7cos(x) + 5 = 0

Remove parenthesis around (2x)
3cos * 2x + -7cos(x) + 5 = 0

Reorder the terms for easier multiplication:
3 * 2cos * x + -7cos(x) + 5 = 0

Multiply 3 * 2
6cos * x + -7cos(x) + 5 = 0

Multiply cos * x
6cosx + -7cos(x) + 5 = 0

Multiply cos * x
6cosx + -7cosx + 5 = 0

Reorder the terms:
5 + 6cosx + -7cosx = 0

Combine like terms: 6cosx + -7cosx = -1cosx
5 + -1cosx = 0

Solving
5 + -1cosx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + -1cosx = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -1cosx = 0 + -5
-1cosx = 0 + -5

Combine like terms: 0 + -5 = -5
-1cosx = -5

Divide each side by '-1osx'.
c = 5o-1s-1x-1

Simplifying
c = 5o-1s-1x-1

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