3cos(2x)=-9cos(x)-6

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Solution for 3cos(2x)=-9cos(x)-6 equation:


Simplifying
3cos(2x) = -9cos(x) + -6

Remove parenthesis around (2x)
3cos * 2x = -9cos(x) + -6

Reorder the terms for easier multiplication:
3 * 2cos * x = -9cos(x) + -6

Multiply 3 * 2
6cos * x = -9cos(x) + -6

Multiply cos * x
6cosx = -9cos(x) + -6

Multiply cos * x
6cosx = -9cosx + -6

Reorder the terms:
6cosx = -6 + -9cosx

Solving
6cosx = -6 + -9cosx

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '9cosx' to each side of the equation.
6cosx + 9cosx = -6 + -9cosx + 9cosx

Combine like terms: 6cosx + 9cosx = 15cosx
15cosx = -6 + -9cosx + 9cosx

Combine like terms: -9cosx + 9cosx = 0
15cosx = -6 + 0
15cosx = -6

Divide each side by '15osx'.
c = -0.4o-1s-1x-1

Simplifying
c = -0.4o-1s-1x-1

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