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3*cos(4*x-(pi/3)) = 0
cos(4*x-(pi/3)) = 0
cos(4*x-(pi/3)) = 0 <=> 4*x-(pi/3) = pi*k_1+pi/2 i k_1 należy do I
t_1 = pi*k_1+pi/2
4*x-t_1-(pi/3) = 0
4*x-t_1-(pi/3) = 0 // + -t_1-(pi/3)
4*x = -(-t_1-(pi/3)) // : 4
x = (-(-t_1-(pi/3)))/4
x = (t_1+pi/3)/4
x = (pi*k_1+pi/2+pi/3)/4 i k_1 należy do I
3*cos(4*x-(pi/3)) = 0 <=> 3 = 0 or 3*cos(4*x-(pi/3)) = 0 <=> cos(4*x-(pi/3)) = 0
x = (pi*k_1+pi/2+pi/3)/4
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