3cos(4x-Pi/3)

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Solution for 3cos(4x-Pi/3) equation: 


x in (-oo:+oo)

3*cos(4*x-(pi/3)) = 0

cos(4*x-(pi/3)) = 0

cos(4*x-(pi/3)) = 0  <=>  4*x-(pi/3) = pi*k_1+pi/2 i k_1 należy do I

t_1 = pi*k_1+pi/2

4*x-t_1-(pi/3) = 0

4*x-t_1-(pi/3) = 0 // + -t_1-(pi/3)

4*x = -(-t_1-(pi/3)) // : 4

x = (-(-t_1-(pi/3)))/4

x = (t_1+pi/3)/4

x = (pi*k_1+pi/2+pi/3)/4 i k_1 należy do I

3*cos(4*x-(pi/3)) = 0  <=>  3 = 0 or 3*cos(4*x-(pi/3)) = 0  <=>  cos(4*x-(pi/3)) = 0

x = (pi*k_1+pi/2+pi/3)/4

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