3cos(x)+4sin(x)=2

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Solution for 3cos(x)+4sin(x)=2 equation:


Simplifying
3cos(x) + 4sin(x) = 2

Multiply cos * x
3cosx + 4sin(x) = 2

Multiply ins * x
3cosx + 4insx = 2

Solving
3cosx + 4insx = 2

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4insx' to each side of the equation.
3cosx + 4insx + -4insx = 2 + -4insx

Combine like terms: 4insx + -4insx = 0
3cosx + 0 = 2 + -4insx
3cosx = 2 + -4insx

Divide each side by '3osx'.
c = 0.6666666667o-1s-1x-1 + -1.333333333ino-1

Simplifying
c = 0.6666666667o-1s-1x-1 + -1.333333333ino-1

Reorder the terms:
c = -1.333333333ino-1 + 0.6666666667o-1s-1x-1

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