3cos(x)+sin(2x)=1

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Solution for 3cos(x)+sin(2x)=1 equation: 


Simplifying
3cos(x) + sin(2x) = 1

Multiply cos * x
3cosx + sin(2x) = 1

Remove parenthesis around (2x)
3cosx + ins * 2x = 1

Reorder the terms for easier multiplication:
3cosx + 2ins * x = 1

Multiply ins * x
3cosx + 2insx = 1

Solving
3cosx + 2insx = 1

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2insx' to each side of the equation.
3cosx + 2insx + -2insx = 1 + -2insx

Combine like terms: 2insx + -2insx = 0
3cosx + 0 = 1 + -2insx
3cosx = 1 + -2insx

Divide each side by '3osx'.
c = 0.3333333333o-1s-1x-1 + -0.6666666667ino-1

Simplifying
c = 0.3333333333o-1s-1x-1 + -0.6666666667ino-1

Reorder the terms:
c = -0.6666666667ino-1 + 0.3333333333o-1s-1x-1

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