3d+12=20+dd=

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Solution for 3d+12=20+dd= equation: 



3d+12=20+dd=

We move all terms to the left:

3d+12-(20+dd)=0

We add all the numbers together, and all the variables

3d-(dd+20)+12=0

We get rid of parentheses

3d-dd-20+12=0

We add all the numbers together, and all the variables

3d-dd-8=0

We move all terms containing d to the left, all other terms to the right

3d-dd=8

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