3d+1=2(d+2)

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Solution for 3d+1=2(d+2) equation: 



3d+1=2(d+2)

We move all terms to the left:

3d+1-(2(d+2))=0



We calculate terms in parentheses: -(2(d+2)), so:

2(d+2)

We multiply parentheses

2d+4

Back to the equation:

-(2d+4)



We get rid of parentheses

3d-2d-4+1=0

We add all the numbers together, and all the variables

d-3=0

We move all terms containing d to the left, all other terms to the right

d=3

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