3d-1/2(2d-8)=-5/4(d+8)

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Solution for 3d-1/2(2d-8)=-5/4(d+8) equation:



3d-1/2(2d-8)=-5/4(d+8)
We move all terms to the left:
3d-1/2(2d-8)-(-5/4(d+8))=0
Domain of the equation: 2(2d-8)!=0
d∈R
Domain of the equation: 4(d+8))!=0
d∈R
We calculate fractions
3d+(-4dd/(2(2d-8)*4(d+8)))+(-(-10d2)/(2(2d-8)*4(d+8)))=0
We calculate terms in parentheses: +(-4dd/(2(2d-8)*4(d+8))), so:
-4dd/(2(2d-8)*4(d+8))
We multiply all the terms by the denominator
-4dd
Back to the equation:
+(-4dd)
We calculate terms in parentheses: +(-(-10d2)/(2(2d-8)*4(d+8))), so:
-(-10d2)/(2(2d-8)*4(d+8))
We add all the numbers together, and all the variables
-(-10d^2)/(2(2d-8)*4(d+8))
We multiply all the terms by the denominator
-(-10d^2)
We get rid of parentheses
10d^2
Back to the equation:
+(10d^2)
determiningTheFunctionDomain 10d^2+3d+(-4dd)=0
We get rid of parentheses
10d^2+3d-4dd=0

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