3e-18=4(-3-(3/4e))

Solution for 3e-18=4(-3-(3/4e)) equation:

3e-18=4(-3-(3/4e))

We move all terms to the left:

3e-18-(4(-3-(3/4e)))=0


Domain of the equation: 4e)))!=0

e!=0/1

e!=0

e∈R


We add all the numbers together, and all the variables

3e-(4(-3-(+3/4e)))-18=0

We multiply all the terms by the denominator


3e*4e)))-(4(-3-(-18*4e)))+3=0

Wy multiply elements

12e^2-72e=0

a = 12; b = -72; c = 0;
Δ = b2-4ac
Δ = -722-4·12·0
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-72}{2*12}=\frac{0}{24}
=0
$
$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+72}{2*12}=\frac{144}{24}
=6
$