3f(2)+5f(-2)-7f(0)=0

Solution for 3f(2)+5f(-2)-7f(0)=0 equation:

3f(2)+5f(-2)-7f(0)=0

We add all the numbers together, and all the variables

3f^2-7f+5f(-2)=0

We multiply parentheses

3f^2-7f-10f=0

We add all the numbers together, and all the variables

3f^2-17f=0

a = 3; b = -17; c = 0;
Δ = b2-4ac
Δ = -172-4·3·0
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-17}{2*3}=\frac{0}{6}
=0
$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+17}{2*3}=\frac{34}{6}
=5+2/3
$