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3f(2)-5=-2(2+1)2+3
We move all terms to the left:
3f(2)-5-(-2(2+1)2+3)=0
We add all the numbers together, and all the variables
3f2-5-(-232+3)=0
We add all the numbers together, and all the variables
3f^2+224=0
a = 3; b = 0; c = +224;
Δ = b2-4ac
Δ = 02-4·3·224
Δ = -2688
Delta is less than zero, so there is no solution for the equation
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