3f+(-10)=26

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Solution for 3f+(-10)=26 equation: 



3f+(-10)=26

We move all terms to the left:

3f+(-10)-(26)=0

determiningTheFunctionDomain
3f-26+(-10)=0

We add all the numbers together, and all the variables

3f-36=0

We move all terms containing f to the left, all other terms to the right

3f=36

f=36/3

f=12

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