3f+2(f+11)+4(2f)=204

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Solution for 3f+2(f+11)+4(2f)=204 equation:


Simplifying
3f + 2(f + 11) + 4(2f) = 204

Reorder the terms:
3f + 2(11 + f) + 4(2f) = 204
3f + (11 * 2 + f * 2) + 4(2f) = 204
3f + (22 + 2f) + 4(2f) = 204

Remove parenthesis around (2f)
3f + 22 + 2f + 4 * 2f = 204

Multiply 4 * 2
3f + 22 + 2f + 8f = 204

Reorder the terms:
22 + 3f + 2f + 8f = 204

Combine like terms: 3f + 2f = 5f
22 + 5f + 8f = 204

Combine like terms: 5f + 8f = 13f
22 + 13f = 204

Solving
22 + 13f = 204

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Add '-22' to each side of the equation.
22 + -22 + 13f = 204 + -22

Combine like terms: 22 + -22 = 0
0 + 13f = 204 + -22
13f = 204 + -22

Combine like terms: 204 + -22 = 182
13f = 182

Divide each side by '13'.
f = 14

Simplifying
f = 14

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