3f-(12-2f)=5(f-2)-2

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Solution for 3f-(12-2f)=5(f-2)-2 equation: 



3f-(12-2f)=5(f-2)-2

We move all terms to the left:

3f-(12-2f)-(5(f-2)-2)=0

We add all the numbers together, and all the variables

3f-(-2f+12)-(5(f-2)-2)=0

We get rid of parentheses

3f+2f-(5(f-2)-2)-12=0



We calculate terms in parentheses: -(5(f-2)-2), so:

5(f-2)-2

We multiply parentheses

5f-10-2

We add all the numbers together, and all the variables

5f-12

Back to the equation:

-(5f-12)



We add all the numbers together, and all the variables

5f-(5f-12)-12=0

We get rid of parentheses

5f-5f+12-12=0

We add all the numbers together, and all the variables

=0

f=0/1

f=0

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