3f-200-30=2f+4000

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Solution for 3f-200-30=2f+4000 equation: 



3f-200-30=2f+4000

We move all terms to the left:

3f-200-30-(2f+4000)=0

We add all the numbers together, and all the variables

3f-(2f+4000)-230=0

We get rid of parentheses

3f-2f-4000-230=0

We add all the numbers together, and all the variables

f-4230=0

We move all terms containing f to the left, all other terms to the right

f=4230

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