3f-40=1/2(f+70)

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Solution for 3f-40=1/2(f+70) equation: 



3f-40=1/2(f+70)

We move all terms to the left:

3f-40-(1/2(f+70))=0



Domain of the equation: 2(f+70))!=0

f∈R



We multiply all the terms by the denominator


3f*2(f+70))-(1-40*2(f+70))=0

Wy multiply elements

6f^2(f-80f(f=0

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