3f-7=5(2f-3)+4

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Solution for 3f-7=5(2f-3)+4 equation: 



3f-7=5(2f-3)+4

We move all terms to the left:

3f-7-(5(2f-3)+4)=0



We calculate terms in parentheses: -(5(2f-3)+4), so:

5(2f-3)+4

We multiply parentheses

10f-15+4

We add all the numbers together, and all the variables

10f-11

Back to the equation:

-(10f-11)



We get rid of parentheses

3f-10f+11-7=0

We add all the numbers together, and all the variables

-7f+4=0

We move all terms containing f to the left, all other terms to the right

-7f=-4

f=-4/-7

f=4/7

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