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3f-81f^2=0
a = -81; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·(-81)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*-81}=\frac{-6}{-162} =1/27 $$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*-81}=\frac{0}{-162} =0 $
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