3g+3(-4-12)=1-g

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Solution for 3g+3(-4-12)=1-g equation: 



3g+3(-4-12)=1-g

We move all terms to the left:

3g+3(-4-12)-(1-g)=0

We add all the numbers together, and all the variables

3g-(-1g+1)+3(-16)=0

We add all the numbers together, and all the variables

3g-(-1g+1)-48=0

We get rid of parentheses

3g+1g-1-48=0

We add all the numbers together, and all the variables

4g-49=0

We move all terms containing g to the left, all other terms to the right

4g=49

g=49/4

g=12+1/4

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