3g+3(-6+2g)=-1-g

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Solution for 3g+3(-6+2g)=-1-g equation: 



3g+3(-6+2g)=-1-g

We move all terms to the left:

3g+3(-6+2g)-(-1-g)=0

We add all the numbers together, and all the variables

3g+3(2g-6)-(-1g-1)=0

We multiply parentheses

3g+6g-(-1g-1)-18=0

We get rid of parentheses

3g+6g+1g+1-18=0

We add all the numbers together, and all the variables

10g-17=0

We move all terms containing g to the left, all other terms to the right

10g=17

g=17/10

g=1+7/10

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