3h(-h+1)=h-1

Solution for 3h(-h+1)=h-1 equation:

3h(-h+1)=h-1

We move all terms to the left:

3h(-h+1)-(h-1)=0

We add all the numbers together, and all the variables

3h(-1h+1)-(h-1)=0

We multiply parentheses

-3h^2+3h-(h-1)=0

We get rid of parentheses

-3h^2+3h-h+1=0

We add all the numbers together, and all the variables

-3h^2+2h+1=0

a = -3; b = 2; c = +1;
Δ = b2-4ac
Δ = 22-4·(-3)·1
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-4}{2*-3}=\frac{-6}{-6}
=1
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+4}{2*-3}=\frac{2}{-6}
=-1/3
$