3h(25h+24)=0

Solution for 3h(25h+24)=0 equation:

3h(25h+24)=0

We multiply parentheses

75h^2+72h=0

a = 75; b = 72; c = 0;
Δ = b2-4ac
Δ = 722-4·75·0
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-72}{2*75}=\frac{-144}{150}
=-24/25
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+72}{2*75}=\frac{0}{150}
=0
$