3h-(h+4)=5+(h-2)

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Solution for 3h-(h+4)=5+(h-2) equation: 



3h-(h+4)=5+(h-2)

We move all terms to the left:

3h-(h+4)-(5+(h-2))=0

We get rid of parentheses

3h-h-(5+(h-2))-4=0



We calculate terms in parentheses: -(5+(h-2)), so:

5+(h-2)

determiningTheFunctionDomain
(h-2)+5

We get rid of parentheses

h-2+5

We add all the numbers together, and all the variables

h+3

Back to the equation:

-(h+3)



We add all the numbers together, and all the variables

2h-(h+3)-4=0

We get rid of parentheses

2h-h-3-4=0

We add all the numbers together, and all the variables

h-7=0

We move all terms containing h to the left, all other terms to the right

h=7

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