3h-2h(4h-5)=10-5h

Solution for 3h-2h(4h-5)=10-5h equation:

3h-2h(4h-5)=10-5h

We move all terms to the left:

3h-2h(4h-5)-(10-5h)=0

We add all the numbers together, and all the variables

3h-2h(4h-5)-(-5h+10)=0

We multiply parentheses

-8h^2+3h+10h-(-5h+10)=0

We get rid of parentheses

-8h^2+3h+10h+5h-10=0

We add all the numbers together, and all the variables

-8h^2+18h-10=0

a = -8; b = 18; c = -10;
Δ = b2-4ac
Δ = 182-4·(-8)·(-10)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-2}{2*-8}=\frac{-20}{-16}
=1+1/4
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+2}{2*-8}=\frac{-16}{-16}
=1
$