3h=7(2/7-3h)-10

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Solution for 3h=7(2/7-3h)-10 equation:



3h=7(2/7-3h)-10
We move all terms to the left:
3h-(7(2/7-3h)-10)=0
Domain of the equation: 7-3h)-10)!=0
We move all terms containing h to the left, all other terms to the right
-3h)-10)!=-7
h!=-7/1
h!=-7
h∈R
We add all the numbers together, and all the variables
3h-(7(-3h+2/7)-10)=0
We multiply all the terms by the denominator
3h*7)-10)-(7(-3h+2=0
We add all the numbers together, and all the variables
-3h+3h*7)-10)-(7(+2=0
Wy multiply elements
21h^2-3h+2=0
a = 21; b = -3; c = +2;
Δ = b2-4ac
Δ = -32-4·21·2
Δ = -159
Delta is less than zero, so there is no solution for the equation

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