3i(6-5i)-4(2+3i)=0

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Solution for 3i(6-5i)-4(2+3i)=0 equation: 



3i(6-5i)-4(2+3i)=0

We add all the numbers together, and all the variables

3i(-5i+6)-4(3i+2)=0

We multiply parentheses

-15i^2+18i-12i-8=0

We add all the numbers together, and all the variables

-15i^2+6i-8=0

a = -15; b = 6; c = -8;
Δ = b2-4ac
Δ = 62-4·(-15)·(-8)
Δ = -444
Delta is less than zero, so there is no solution for the equation

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