3i+27=5(1+5i)

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Solution for 3i+27=5(1+5i) equation: 



3i+27=5(1+5i)

We move all terms to the left:

3i+27-(5(1+5i))=0

We add all the numbers together, and all the variables

3i-(5(5i+1))+27=0



We calculate terms in parentheses: -(5(5i+1)), so:

5(5i+1)

We multiply parentheses

25i+5

Back to the equation:

-(25i+5)



We get rid of parentheses

3i-25i-5+27=0

We add all the numbers together, and all the variables

-22i+22=0

We move all terms containing i to the left, all other terms to the right

-22i=-22

i=-22/-22

i=1

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