3i+3=3(i+1)

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Solution for 3i+3=3(i+1) equation: 



3i+3=3(i+1)

We move all terms to the left:

3i+3-(3(i+1))=0



We calculate terms in parentheses: -(3(i+1)), so:

3(i+1)

We multiply parentheses

3i+3

Back to the equation:

-(3i+3)



We get rid of parentheses

3i-3i-3+3=0

We add all the numbers together, and all the variables

=0

i=0/1

i=0

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