3i+4(3i-5)=28-i

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Solution for 3i+4(3i-5)=28-i equation:


Simplifying
3i + 4(3i + -5) = 28 + -1i

Reorder the terms:
3i + 4(-5 + 3i) = 28 + -1i
3i + (-5 * 4 + 3i * 4) = 28 + -1i
3i + (-20 + 12i) = 28 + -1i

Reorder the terms:
-20 + 3i + 12i = 28 + -1i

Combine like terms: 3i + 12i = 15i
-20 + 15i = 28 + -1i

Solving
-20 + 15i = 28 + -1i

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add 'i' to each side of the equation.
-20 + 15i + i = 28 + -1i + i

Combine like terms: 15i + i = 16i
-20 + 16i = 28 + -1i + i

Combine like terms: -1i + i = 0
-20 + 16i = 28 + 0
-20 + 16i = 28

Add '20' to each side of the equation.
-20 + 20 + 16i = 28 + 20

Combine like terms: -20 + 20 = 0
0 + 16i = 28 + 20
16i = 28 + 20

Combine like terms: 28 + 20 = 48
16i = 48

Divide each side by '16'.
i = 3

Simplifying
i = 3

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