3j+17=j-5

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Solution for 3j+17=j-5 equation: 



3j+17=j-5

We move all terms to the left:

3j+17-(j-5)=0

We get rid of parentheses

3j-j+5+17=0

We add all the numbers together, and all the variables

2j+22=0

We move all terms containing j to the left, all other terms to the right

2j=-22

j=-22/2

j=-11

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