3j+2(j-5)=35

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Solution for 3j+2(j-5)=35 equation: 



3j+2(j-5)=35

We move all terms to the left:

3j+2(j-5)-(35)=0

We multiply parentheses

3j+2j-10-35=0

We add all the numbers together, and all the variables

5j-45=0

We move all terms containing j to the left, all other terms to the right

5j=45

j=45/5

j=9

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