3j+6=-3(2j-2)

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Solution for 3j+6=-3(2j-2) equation: 



3j+6=-3(2j-2)

We move all terms to the left:

3j+6-(-3(2j-2))=0



We calculate terms in parentheses: -(-3(2j-2)), so:

-3(2j-2)

We multiply parentheses

-6j+6

Back to the equation:

-(-6j+6)



We get rid of parentheses

3j+6j-6+6=0

We add all the numbers together, and all the variables

9j=0

j=0/9

j=0

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