3k(2+b+4a)=

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Solution for 3k(2+b+4a)= equation: 


Simplifying
3k(2 + b + 4a) = 0

Reorder the terms:
3k(2 + 4a + b) = 0
(2 * 3k + 4a * 3k + b * 3k) = 0

Reorder the terms:
(12ak + 3bk + 6k) = 0
(12ak + 3bk + 6k) = 0

Solving
12ak + 3bk + 6k = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-3bk' to each side of the equation.
12ak + 3bk + -3bk + 6k = 0 + -3bk

Combine like terms: 3bk + -3bk = 0
12ak + 0 + 6k = 0 + -3bk
12ak + 6k = 0 + -3bk
Remove the zero:
12ak + 6k = -3bk

Add '-6k' to each side of the equation.
12ak + 6k + -6k = -3bk + -6k

Combine like terms: 6k + -6k = 0
12ak + 0 = -3bk + -6k
12ak = -3bk + -6k

Divide each side by '12k'.
a = -0.25b + -0.5

Simplifying
a = -0.25b + -0.5

Reorder the terms:
a = -0.5 + -0.25b

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