3k+(-2)=10

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Solution for 3k+(-2)=10 equation: 



3k+(-2)=10

We move all terms to the left:

3k+(-2)-(10)=0

determiningTheFunctionDomain
3k-10+(-2)=0

We add all the numbers together, and all the variables

3k-12=0

We move all terms containing k to the left, all other terms to the right

3k=12

k=12/3

k=4

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