3k+12=3(k+4)

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Solution for 3k+12=3(k+4) equation: 



3k+12=3(k+4)

We move all terms to the left:

3k+12-(3(k+4))=0



We calculate terms in parentheses: -(3(k+4)), so:

3(k+4)

We multiply parentheses

3k+12

Back to the equation:

-(3k+12)



We get rid of parentheses

3k-3k-12+12=0

We add all the numbers together, and all the variables

=0

k=0/1

k=0

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