3k+20=10-(5k+6)

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Solution for 3k+20=10-(5k+6) equation: 



3k+20=10-(5k+6)

We move all terms to the left:

3k+20-(10-(5k+6))=0



We calculate terms in parentheses: -(10-(5k+6)), so:

10-(5k+6)

determiningTheFunctionDomain
-(5k+6)+10

We get rid of parentheses

-5k-6+10

We add all the numbers together, and all the variables

-5k+4

Back to the equation:

-(-5k+4)



We get rid of parentheses

3k+5k-4+20=0

We add all the numbers together, and all the variables

8k+16=0

We move all terms containing k to the left, all other terms to the right

8k=-16

k=-16/8

k=-2

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