3k+4(k+1)+(3k+1)+6=36

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Solution for 3k+4(k+1)+(3k+1)+6=36 equation: 



3k+4(k+1)+(3k+1)+6=36

We move all terms to the left:

3k+4(k+1)+(3k+1)+6-(36)=0

We add all the numbers together, and all the variables

3k+4(k+1)+(3k+1)-30=0

We multiply parentheses

3k+4k+(3k+1)+4-30=0

We get rid of parentheses

3k+4k+3k+1+4-30=0

We add all the numbers together, and all the variables

10k-25=0

We move all terms containing k to the left, all other terms to the right

10k=25

k=25/10

k=2+1/2

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