3k+4=3(k+4/3)

Solution for 3k+4=3(k+4/3) equation:

3k+4=3(k+4/3)

We move all terms to the left:

3k+4-(3(k+4/3))=0

We add all the numbers together, and all the variables

3k-(3(+k+4/3))+4=0

We multiply all the terms by the denominator


3k*3))-(3(+k+4+4*3))=0

We add all the numbers together, and all the variables

3k*3))-(3(k+16))=0

We add all the numbers together, and all the variables

3k*3))-(3(k=0

Wy multiply elements

9k^2=0

a = 9; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·9·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$k=\frac{-b}{2a}=\frac{0}{18}=0$