3k-(k+4)=4(k+2)-2

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Solution for 3k-(k+4)=4(k+2)-2 equation: 



3k-(k+4)=4(k+2)-2

We move all terms to the left:

3k-(k+4)-(4(k+2)-2)=0

We get rid of parentheses

3k-k-(4(k+2)-2)-4=0



We calculate terms in parentheses: -(4(k+2)-2), so:

4(k+2)-2

We multiply parentheses

4k+8-2

We add all the numbers together, and all the variables

4k+6

Back to the equation:

-(4k+6)



We add all the numbers together, and all the variables

2k-(4k+6)-4=0

We get rid of parentheses

2k-4k-6-4=0

We add all the numbers together, and all the variables

-2k-10=0

We move all terms containing k to the left, all other terms to the right

-2k=10

k=10/-2

k=-5

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