3k-(k+4)=4(k-2)-6

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Solution for 3k-(k+4)=4(k-2)-6 equation: 



3k-(k+4)=4(k-2)-6

We move all terms to the left:

3k-(k+4)-(4(k-2)-6)=0

We get rid of parentheses

3k-k-(4(k-2)-6)-4=0



We calculate terms in parentheses: -(4(k-2)-6), so:

4(k-2)-6

We multiply parentheses

4k-8-6

We add all the numbers together, and all the variables

4k-14

Back to the equation:

-(4k-14)



We add all the numbers together, and all the variables

2k-(4k-14)-4=0

We get rid of parentheses

2k-4k+14-4=0

We add all the numbers together, and all the variables

-2k+10=0

We move all terms containing k to the left, all other terms to the right

-2k=-10

k=-10/-2

k=+5

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