3k-12=2(k-6)

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Solution for 3k-12=2(k-6) equation: 



3k-12=2(k-6)

We move all terms to the left:

3k-12-(2(k-6))=0



We calculate terms in parentheses: -(2(k-6)), so:

2(k-6)

We multiply parentheses

2k-12

Back to the equation:

-(2k-12)



We get rid of parentheses

3k-2k+12-12=0

We add all the numbers together, and all the variables

k=0

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