3k-14=(k-5)+1

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Solution for 3k-14=(k-5)+1 equation: 



3k-14=(k-5)+1

We move all terms to the left:

3k-14-((k-5)+1)=0



We calculate terms in parentheses: -((k-5)+1), so:

(k-5)+1

We get rid of parentheses

k-5+1

We add all the numbers together, and all the variables

k-4

Back to the equation:

-(k-4)



We get rid of parentheses

3k-k+4-14=0

We add all the numbers together, and all the variables

2k-10=0

We move all terms containing k to the left, all other terms to the right

2k=10

k=10/2

k=5

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