3k-14=3(1k-5)+1

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Solution for 3k-14=3(1k-5)+1 equation:



3k-14=3(1k-5)+1
We move all terms to the left:
3k-14-(3(1k-5)+1)=0
We add all the numbers together, and all the variables
3k-(3(k-5)+1)-14=0
We calculate terms in parentheses: -(3(k-5)+1), so:
3(k-5)+1
We multiply parentheses
3k-15+1
We add all the numbers together, and all the variables
3k-14
Back to the equation:
-(3k-14)
We get rid of parentheses
3k-3k+14-14=0
We add all the numbers together, and all the variables
=0
k=0/1
k=0

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