3k-2(K+3)=k

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Solution for 3k-2(K+3)=k equation: 



3k-2(+3)=k

We move all terms to the left:

3k-2(+3)-(k)=0

We add all the numbers together, and all the variables

3k-k-23=0

We add all the numbers together, and all the variables

2k-23=0

We move all terms containing k to the left, all other terms to the right

2k=23

k=23/2

k=11+1/2

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